Quant Quiz
1. A man takes 5hr 45min in walking to certain place and riding back. He would have gained 2hrs by riding both ways. The time he would take to walk both ways is?
A. 8 hr 45 min
B. 6 hr 28 min
C. 7 hr 45 min
D. 10 hr 45 min
A. 15 seconds
B. 30 seconds
C. 25 seconds
D. 20 seconds
3. There are ratio of 2 : 4 : 5 : 7 between the angle of quadrilateral. While largest angle of triangle is 20 less than 5/7 of largest angle of quadrilateral. The smallest angle of triangle is 2/5 of largest angle of triangle. What will be the second largest angle?
A. 68°
B. 112°
C. 132°
D. 100°
4. While finding the average of ‘9’ consecutive numbers starting from X; a student interchanged the digits of second number by mistake and got the average which is 8 more than the actual. What is X?
A. 13
B. 15
C. 17
D. 18
5. My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my father was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, then what was the age my father and mother respectively when my brother was born.
A. 32 yrs, 23yrs
B. 32 yrs, 29yrs
C. 35 yrs, 29yrs
D. Cannot Be Determined
6. A tradesman gives 4% discount on the marked price and gives article free for buying every 15 articles and thus gains 35%. The marked price is above the cost price by?
A. 50% above C.P
B. 55% above C.P
C. 60% above C.P
D. 65% above C.P
7. Ram, Karan and Rohan invested capital in the ratio of 2:3:4 for time period of 6:4:3. Find the ratio of profit distributed?
A. 12:13:14
B. 13:12:14
C. 13:14:12
D. None of these
8. In a 729 litres mixture of milk and water, the ratio of milk to water is 7 : 2. To get a new mixture containing milk and water in the ratio 7 : 3, the amount of water to be added is
A. 81 litres
B. 71 litres
C. 56 litres
D. 50 litres
9. A Sum was put at S.I. at a certain rate for 3 years Had it been put at 2% higher rate, it would have fetched Rs. 360 more. Find the Sum.
A. Rs. 5000
B. Rs. 6000
C. Rs. 8000
D. Rs. 7500
10. A can do a piece of work in 80 days. He works at it for 10 days & then B alone finishes the remaining work in 42 days. In how much time will A and B, working together, finish the work?
A. 31 Days
B. 60 Days
C. 30 Days
D. 75 Days
Answers with Detailed Explanations:
1. (C):
Let x be the speed of walked
Let y be the speed of ride
Let D be the distance
Then D/x + D/y = 23/4 hr -------1
D/y + D/y = 23/4 – 2 hr
D/y = 15/8 --------2
Substitute 2 in 1
D/x + 15/8 = 23/4 = D/x = 23/4 -15/8 =46-15/8 =31/8
Time taken for walk one way is 31/8 hr
Time taken to walk to and fro is 2 x 31/8 = 31/4 hr =7 hr 45 min
2. (B):
180 / 20 = 9 m/s
Let his initial speed = x
After increasing 50% his speed will 1.5 x = 9/1.5 = 6 m/s
So, time taken = 180/6 = 30 sec
3. (A):
Quadrilateral largest angle = (360 x 7) / 18 = 140 degrees
Largest angle of triangle = (140 x 5) / 7 – 20 = 80 degrees
Smallest angle = (80 x 2) / 5 = 32 degrees
Second largest angle = 180 - (80 + 32)
= 180 – 112 = 68 degrees
4. (D):
Since the average is 8 more than the actual, the second no will increase by 72 (9 x 8) by interchanging the digits.
If ab is the second no,
then 10a + b + 72 = 10b+ a
i.e. 9 (b - a) = 72
b - a = 8.
The possible number ab is 19. Since the second no is 19.
The first no is 18
So X = 18
5. (D)
6. (A):
Let the C.P of each article be Rs 100
Then C.P of 16 articles=Rs (100 * 16) = Rs 1600
S.P of 15 articles =1600*(135/100) = Rs 2160
S.P of each article =2160/15=Rs 144
If S.P is Rs 96, marked price =Rs 100
If S.P is Rs 144, marked price =(100/96)*144=Rs 15000
Therefore marked price=50% above C.P
7. (D):
Ratio of profit be
2 x 6 : 3 x 4 : 4 x 3 = 12 : 12: 12 = 1 : 1 : 1
8. (A):
Quantity of milk in 729 litres of mixture
= (7 x 729) / 9 = 567 litres
Quantity of water
= (729-567) litres = 162 litre.
Let x litres of water is mixed to get the required ratio of 7 : 3
= 567 / (162 + x)= 7 / 3
= 7x + 1134 = 1701
= 7x = 1701 – 1134 = 567
= x = 567 / 7 = 81 litres
9. (B):
Let Sum =P
Original rate = R
T = 3 years
If 2% is more than the original rate, it would have fetched 360 more i.e., R+2
(P x (R+2) x 3/10 0) - (P x R x 3) /100 = 360 = 3PR+ 6P-3PR = 36000 = 6P = 36000 = P = 6000
10. (C):
Work done by A in 10 days=10/80=1/8
Remaining work=(1-(1/8))=7/8
Now, work will be done by B in 42 days.
Whole work will be done by B in (42*8/7)=48 days
Therefore, A's one day's work=1/80
B’s one day's work=1/48
(A+B)'s one day's work=1/80+1/48=8/240=1/30
Hence, both will finish the work in 30 days.
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