Friday 18 August 2017

Quantitative Aptitude


1. What is the place value of 7 in the numeral 2734? 
A.70B.7
C.700D.7.00
Answer: Option C
Explanation: 
7 × 100 = 700

2. Find the product of the local value and absolute value of 4 in 564823
A.1600B.8000
C.16000D.12000
Answer: Option C
Explanation: 
Place value = Local value
Face value = Absolute value
The place value of 4 in 564823 is 4 x 1000 = 4000
The face value of 4 in 564823 is nothing but 4.
=> 4000 x 4 = 16000

3. Find the product of the place value and face value of 3 in 5769354
A.900B.9000
C.90D.9
Answer: Option A
Explanation: 
Place value = Local value
Face value = Absolute value
The place value of 3 in 5769354 is 3 x 100 = 300
The face value of 3 in 5769354 is nothing but 3.
=> 300 x 3 = 900

4. What is the least value of x, so that 23x57 is divisible by 3.
A.2B.0
C.1D.3
Answer: Option C
Explanation: 
23257 is not divisible by 3
23057 is not divisible by 3
23157 is divisible by 3
23357 is not divisible by 3
2+3+1+5+7 = 18
18/3 = 6.
x = 1

5. What is the least value of p, so that 123p578 is divisible by 11
A.7B.8
C.6D.5
Answer: Option B
Explanation: 
123p578
1 + 3 + 5 + 8 = 17
2 + p + 7 = 17
=> 9 + p = 17
=> p = 17 - 9 
=> p = 8

6. Find the prodect of the local value and absolute value of 4 in 23468
A.400B.1600
C.1200D.80
Answer: Option B
Explanation: 
Local value of 4 = 4 x 100 = 400
Place value of 4 = 4
There fore = 4 x 400 = 1600

7. What is the least value of x. So that 23x57 is divisible by 3.
A.2B.0
C.1D.3
Answer: Option C
Explanation: 
The sum of the digits of the number is divisible by 3, then the number is divisible by3.
2 + 3 + x + 5 + 7 = 17 + x
Least value of x may be 1
Therefore 17 + 1 = 18 is divisible by 3.

8. What is the least value of x, So that 2x5472 is divisible by 9
A.7B.8
C.9D.3
Answer: Option A
Explanation: 
The sum of the digits of the number is divisible by 9.
Then the number is divisible by 9.
2 + x + 5 + 4 + 7 + 2 = 20 + x
Least value of x may be '7',
So that the total 20 + 7 = 27
is divisible by 9.

 

9. What is the least value of k. So that 123k578 is divisible by 11.
A.8B.7
C.5D.6
Answer: Option A
Explanation: 
The Difference of the sum of the digits at odd place and the sum of the digits at even place of the number, is either 0 or a number divisible by 11.
(1 + 3 + 5 + 8) - (2 + k + 7) = 17 - 9 - k = 8 - k 
Therefore if k = 8, then the value become zero.
k = 8 is the least value 
so that 123k578 is divisible by 11.

10. Which is the following is divisible by 11.
A.4305B.4825
C.4805D.4905
Answer: Option D
Explanation: 
Sum of first 'n' natural numbers = n(n + 1)/2
Sum of first 9 natural numbers = 9(9 + 1)//2 = 9 x 5 = 45
Sum of first 99 natural numbers = 99(99 + 1)//2 = 99 x 50 = 4950
4950 - 45 = 4905


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