Important Quant Quiz

Important Quant Quiz

1) A train 150 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train? 

 A.    5 sec

 B.    9 sec

 C.    12 sec

 D.    15 sec

2) A train is moving at a speed of 132 km/hr. If the length of the train is 110 metres, how long will it take to cross a railway platform 165 metres long?

 A.    7½ sec

 B.    10 sec

 C.    12 ½ sec

 D.    15 sec

3) A man sitting in a train which is traveling at 50 kmph observes that a goods train, traveling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed.?

 A.    50 kmph

 B.    58 kmph

 C.    62 kmph

 D.    65 kmph

4) A train 220 m long is running with a speed of 59 kmph. In what time will it pass a man who is running at 7 kmph in the direction opposite to that in which the train is going?

A.    7 sec

B.    8 sec

C.    10 sec

D.    12 sec

5) A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?

A.    180 m

B.    240 m

C.    260 m

D.    280 m

6) Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

A.    28 sec

B.    36 sec

C.    48 sec

D.    52 sec

7) A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?

A.    230 m

B.    245 m

C.    260 m

D.    275 m

8) Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:

 A.    10.8 sec

 B.    9.5 sec

 C.    7.4 sec

 D.    8.9 sec

9) Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:

A.    18 km/hr

B.    26 km/hr

C.    36 km/hr

D.    42 km/hr

10) Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?

A.    8 sec

B.    12 sec

C.    15 sec

D.    10 sec

Answers with Explanation: - 

 

1.       Answer : B.

    Speed of the train relative to man = (68 - 8) kmph

   = (60* 5/18) m/sec = (50/3)m/sec

   Time taken by the train to cross the man

    = Time taken by It to cover 150 m at 50/3 m / sec 

    = 150 *3/ 50 sec   = 9sec

2.       Answer : A.

Speed of train = 132 *(5/18) m/sec = 110/3 m/sec.

Distance covered in passing the platform = (110 + 165) m = 275 m.

Time taken =275 *(3/110) sec =15/2 sec = 7 ½ sec

3.       Answer : C.

Relative speed = 280/9 m / sec = ((280/9)*(18/5)) kmph = 112 kmph.

Speed of goods train = (112 - 50) kmph = 62 kmph.

4.       Answer : D.

Speed of the train relative to man = (59 + 7) kmph

= 66 *5/18 m/sec = 55/3 m/sec.

Time taken by the train to cross the man = Time taken by it to cover 220 m at (55/3) m / sec

= (220 *3/55) sec = 12 sec

5.       Answer : B.

Speed = 54 x 5/18 = 15 m/s

Length of the train = (15 x 20)m = 300 m.

Let the length of the platform be x metres.

Then, (x + 300)/36 = 15

--> x + 300 = 540

x = 240m.

6.       Answer : C.

Relative speed = (60+ 90) km/hr

= 150x5/18

= 120/3 m/sec

Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.

Required time = 2000 x 3/125 = 48 sec

7.       Answer : A.

Relative speed = (120 + 80) km/hr

= 200 x 5/18

= 500/9 m/sec

Then, (x+270)/9 = 500/9

--> x + 270 = 500

--> x = 230.

8.       Answer : A.

Relative speed = (60 + 40) km/hr = 100x5/18 = 250/9 m/ sec.

Distance covered in crossing each other = (140 + 160) m = 300 m.

Required time = 300x9/250 = 54/5 = 10.8 sec.

9.       Answer : C.

Let the speed of each train be x m/sec.

Then, relative speed of the two trains = 2x m/sec.

So, 2x = (120 + 120)/12

--> 2x = 20

--> x = 10.

--> Speed of each train = 10 m/sec = 10 x 18/5 km/hr = 36 km/hr.

10.   Answer : B.

Speed of the first train = 120/10 m/sec = 12 m/sec.

Speed of the second train = 120/15 m/sec = 8 m/sec.

Relative speed = (12 + 8) = 20 m/sec.

Required time = (120 + 120)/20 sec = 12 sec.