Data Interpretation
Directions (1-5): Study the following arrangement carefully and answer the questions given below.
In an exhibition of watches there were three companies HMT, ROMAX and TITAN who introduced their models in the exhibition and it is found at the last of the exhibition that total -
300 customers have visited exhibition. 50% customers purchased HMT; 55% customers purchased TITAN; 45% customers purchased ROMAX. 20% of customers who purchased HMT -
also purchased other two brands. Customers who purchased any of two brands are 95. Customers of only HMT are 20 more than that of only ROMAX. Customers who purchased only HMT and ROMAX are 40.
300 customers have visited exhibition. 50% customers purchased HMT; 55% customers purchased TITAN; 45% customers purchased ROMAX. 20% of customers who purchased HMT -
also purchased other two brands. Customers who purchased any of two brands are 95. Customers of only HMT are 20 more than that of only ROMAX. Customers who purchased only HMT and ROMAX are 40.
1.How many of them did not purchase any of the three watches?
(a) 15
(b) 20
(c) 05
(d) 10
(5) None of these
2.How many of them purchased only one brand of watches?
(a) 175
(b) 160
(c) 165
(d) 170
(5) None of these
3.How many of them purchased at least two brands of watches?
(a) 125
(b) 105
(c) 95
(d) 130
(5) None of these
4.How many of them didn’t purchase only one ROMAX watch?
(a) 160
(b) 105
(c) 260
(d) 265
(5) None of these
5.What is the total number of watches which have been sold?
(a) 450
(b) 445
(c) 455
(d) 305
(5) None of these
Directions (6-10): Following bar-graph shows the percentage of passed girls with respect to total passed students of two colleges A and B.
6. If the number of boys passed from College A and College B is 220 and 175 respectively in the year 2002,
then what is the difference between number of girls passed from A and B in year 2002?
then what is the difference between number of girls passed from A and B in year 2002?
(a) 75
(b) 80
(c) 95
(d) 105
(5) None of these
7. If the number of girls passed from College A and College B in year 2001 is equal to 70, then what is the sum of total number of passed students of College A and College B in the same year?
(a) 445
(b) 415
(c) 405
(d) 375
(5) None of these
8. If the number of girls passed from College A in year 2004 is equal to the number of boys passed from College B in year 2002 and it is 105,
then what is the difference to total number of students passed from College A in 2004 and College B in year 2002?
then what is the difference to total number of students passed from College A in 2004 and College B in year 2002?
(a) 25
(b) 30
(c) 35
(d) 40
(5) None of these
9.If total number of students passed from College A and College B in year 2005 is 400 and 500 respectively, then number of girls passed from -
College B is how much percent more than the number of girls passed from College A in the same year?
College B is how much percent more than the number of girls passed from College A in the same year?
(a) 25/2%
(b)35/2%
(c)20/9
(d)8/7
(5) None of these
10. If the number of girls passed from College A and College B in year 2003 is 200 and 240 respectively, then number of boys passed from College B-
is what percent of number of boys passed from College A in same year?
is what percent of number of boys passed from College A in same year?
(a) 80%
(b) 110%
(c) 120%
(d) 130%
(5) None of these
Answer:
1.c
2.d
3.a
4.d
5.a
6.d;
Total number of passed students of College A =(100*220)/55 = 400
Number of girls passed = 45% of 400 = 180
Total number of passed students of College= (100*175)70 = 250
Number of girls passed = 30% of 250 = 75
Difference = 180 – 72 = 105
7.d;
For College A,
35% of girls = 70
Total student =(70*100)/35 = 200
For College B,
40% of girls = 70
Total student = (70*100)/40 = 175
Sum = 200 + 175 = 375
8.a;
Total students passed of College A in 2004 = 175
Total students passed of College B in 2002 = 150
Difference = 175 – 150 = 25
9.c;
Number of girls passed of College= (44*400)/100 =176 Number of girls passed of College B =(36*500)/100 = 180
% difference = [(180-176)/180]*100=20/9
10.d;
Number of girls passed from College A = Number of boys passed from College A = 200
Number of girls passed from College B = 48% = 240
Total passed=(240/200)*48=500
Number of boys passed=52% of 500 = 260
%=(260/200)*100=130%
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