Data Interpretation Quiz

 Data Interpretation Quiz

Directions—(1–5) Study the following table carefully to answer these questions:
Percentage of Marks obtained by six students in six subjects

1. What are the average marks obtained by all the students in Maths ?
(1) 75 
(2) 112.50
(3) 108.50 
(4) 78
(5) None of these

2. What are the average marks obtained by all students in Chemistry?
(1) 54.25
(2) 54.75
(3) 73
(4) 71
(5) None of these

3. What is the ratio between total marks obtained by D in Biology, 

Maths and English together and the total marks obtained by F in these subjects together respectively?
(1) 209 : 215
(2) 215 : 209
(3) 206 : 223
(4) 223 : 206
(5) None of these

4. Marks obtained by C in Maths are approximately-

 what per cent of his total marks obtained in all the six subjects together ?
(1) 22 
(2) 16
(3) 20 
(4) 18
(5) 28

5. What are the total marks obtained by ‘B’ in all the subjects together ?
(1) 336 
(2) 223
(3) 446 
(4) 273
(5) None of these

Directions:- (6-10)

The following line graph gives the percentage of the number of candidates who qualified an examination out of the total number of candidates who appeared for the-

 examination over a period of seven years from 2003 to 2009.
Percentage of Candidates Qualified to Appeared in an Examination Over the Years

6. If the number of students appeared in the examination in 2004 and 2005 were in the ratio 2 : 3, then find the ratio of qualified students from these years?
(1) 2 : 3
(2) 5 : 6
(3) 4 : 5
(4) 8 : 15
(5) None of these

7. In which pair of years was the number of candidates qualified the same?
(1) 2004 and 2006
(2) 2004 and 2009
(3) 2007 and 2008
(4) 2006 and 2007
(5) Data inadequate

8. If the number of candidates qualified in 2007 was 5800, what was the number of candidates appeared in 2007?
(1) 7520
(2) 7250
(3) 7500
(4) 72500
(5) cannot be determined

9. If the total number of candidates appeared in 2005 and 2006 together was 42400,

 then the total number of candidates qualified in these two years together was?
(1) 34700
(2) 32100
(3) 31500
(4) 35200
(5) Data inadequate

10. The total number of candidates qualified in 2008 and 2009 together was 6600 and the number of candidates appeared in 2008 was 5100.

 What was the number of candidates appeared in 2009?
(1) 4000
(2) 4850
(3) 4200
(4) 4150 
(5) None of these

ANSWERS
Solutions (1-5)
1. (2)
Required Average = (76 + 84 + 66 + 72 + 88 + 64)/6 * 150/100 = 112.5

2. (2)
Required Average = (66 + 72 + 78 + 80 + 68 + 74)/6 * 75/100 = 54.75

3. (1)
Total marks obtained by D in Biology, Maths and English together = 68% of 100 + 72% of 150 + 66% of 50 = 209
Total marks obtained by F in Biology, Maths and English together = 79% of 100 + 64% of 150 + 80% of 50 = 215
Required ratio = 209 : 215

4. (5)
Required % = 66% of 150/(56%of75 + 78%of75 + 71%of100 + 66%of150 + 86%of50 + 70%of50) * 100 = 28% (approx)

5. (5)
Total marks obtained by ‘B’ in all the subjects together
= 76% of 75 + 72% of 75 + 65% of 100 + 84% of 150 + 74% of 50 + 75% of 50
= 376.5

Solutions (6-10)
6. (5)  Required ratio = 50% of 2 : 60% of 3 = 5 : 9

7. (5)
Since the number of candidates appeared for the exam is not given, we cannot find the number of candidates who cleared the exam.

8. (2)
Required number = 5800/0.8 = 7250

9. (5)
Since we don’t know the number of candidates appeared in 2005 and 2006 individually, we cannot find the number of qualified candidates.

10. (3)
Let the number of candidates appeared in 2009 was x. Then
80% of 5100 + 60% of x = 6600
x = 4200