Directions (1-4): Study the following table carefully to answer the questions that follow.
Number (N) of six type of Electronic Products sold by Six different stores in a month and the price per product (P) (price in Rs ‘000) charged by each Store
Store
|
A
|
B
|
C
|
D
|
E
|
F
| ||||||
Product
|
N
|
P
|
N
|
P
|
N
|
P
|
N
|
P
|
N
|
P
|
N
|
P
|
L
|
54
|
135
|
48
|
112
|
60
|
104
|
61
|
124
|
40
|
136
|
48
|
126
|
M
|
71
|
4.5
|
53
|
3.8
|
57
|
5.6
|
49
|
4.9
|
57
|
5.5
|
45
|
4.7
|
N
|
48
|
12
|
47
|
18
|
52
|
15
|
54
|
11.5
|
62
|
10.5
|
56
|
11
|
O
|
52
|
53
|
55
|
48
|
48
|
50
|
54
|
49
|
59
|
47
|
58
|
51
|
P
|
60
|
75
|
61
|
68
|
56
|
92
|
44
|
84
|
46
|
76
|
59
|
78
|
Q
|
43
|
16
|
44
|
15
|
45
|
14.5
|
48
|
15.6
|
55
|
18.2
|
55
|
14.9
|
Q1. What is the total amount earned by Store C through the sale of M and O type products together?
(a) Rs 2719.2 lakh
(b) Rs 271.92 lakh
(c) Rs 2.7192 lakh
(d) Rs 27.192 lakh
(e) None of these
S1. Ans.(d)
Sol. Total amount earned by store C through the sales of M and O type products together
= (57 × 5.6 + 48 × 50) thousand
= (319.2 + 2400) thousand
= 27.192 lakh
Q2. Number of L type product sold by Store F is what percent of the number same type of products sold by Store E?
(a) 76.33
(b) 124
(c) 83.33
(d) 115
(e) None of these
S2. Ans.(e)
Sol. Number of L type product sold by store F = 48
Number of L type product sold by store E = 40
Required percentage = 48/40*100 =120
Q3. What is the difference in the amount earned by Store A through the sale of P type products and that earned by Store B through the sale of Q type products?
(a) Rs 38.4 lakh
(b) Rs 0.384 lakh
(c) Rs 3.84 lakh
(d) Rs 384 lakh
(e) None of these
S3. Ans.(a)
Sol. Required difference
= (60 × 75 – 44 × 15) thousand
= (4500 – 660) thousand
= 38.4 lakh
Q4. What is the respective ratio of total number of N and L type products together sold by Store D and the same products sold by Store A?
(a) 119 : 104
(b) 102 : 115
(c) 104 : 115
(d) 117 : 103
(e) None of these
S4. Ans.(e)
Sol. Required ratio = (61 + 54) : (54 + 48) = 115 : 102
Directions (5-10): Study the following graph to answer the given questions.
Q5. If the income of Company X in 1998-99 was equal to the expenditure of Company Y in 2001-2002, what was the ratio of their respective profits?
(a) 13:15
(b) 15:26
(c) 13:26
(d) Cannot be determined
(e) None of these
Q6. For Company X, its income in 2001-2002 was equal to its expenditure in 2002-2003, what was the ratio of its respective incomes in these two years?
(a) 4:5
(b) 3:4
(c) 2:3
(d) Cannot be determined
(e) None of these
Q7. For Company Y, in which year is the percent of increase in percent profit over that of previous year the highest?
(a) 2002-03
(b) 1999-2000
(c) 2001-02
(d) Cannot be determined
(e) None of these
Q8. In 1997-98, the expenditure of Company X was Rs. 40 crores. What was its income in that year?
(a) Rs. 50 crore
(b) Rs. 48 crore
(c) Rs. 46 crore
(d) Cannot be determined
(e) None of these
S8. Ans.(b)
Sol. Required income
= 120% of Rs. 40 Crore = Rs. 48 Crore
Q9. What was the difference in the expenditures of the two companies in 1999-2000?
(a) 10
(b) 100
(c) 1000
(d) Cannot be determined
(e) None of these
S9. Ans.(d)
Sol. The given graph depicts only the percent profit earned by the two companies over the given years. Hence, these information are insufficient to answer the question.
Q10. In 2002-03 the income of Company Y was Rs. 128 crores. What was its expenditure in that year?
(a) Rs. 76.8 crore
(b) Rs. 64 crore
(c) Rs. 48 crore
(d) Cannot be determined
(e) None of these
S10. Ans.(e)
Sol. In 2002 – 03 profit earned by company Y was 60%
Therefore, 160% of expenditure Rs. 128 crore
Thus, required expenditure = 128/160× 100 = Rs. 80 Crores
Directions (11-15): Study the following information to answer the given questions.
Percentage of students in various courses (A, B, C, D, E, F) in pie chart I and percentage of girls in pie chart II.
Total students: 1200 (800 girls + 400 boys)
Q11. For course D, what is the respective ratio of boys and girls?
(a) 3:4
(b) 4:5
(c) 3:5
(d) 5:6
(e) None of these
S11. Ans.(a)
Sol. Total number of students for course D = 35% of 1200 = 420
Number of girl students for course D = 30% of 800 = 240
Number of boy students for course D = 420 – 240 = 180
Required ratio = 180 : 240 = 3 : 4.
Q12. For which pair of courses is the number of boys the same?
(a) E and F
(b) A and D
(c) C and F
(d) B and D
(e) None of these
S12. Ans.(c)
Sol. Number of boys for different courses are
A = 0; B = 100; C = 44; D = 180; E = 32; F = 44.
Q13. For course E, the number of girls is how much percent more than the number of boys for course E?
(a) 250
(b) 350
(c) 150
(d) 80
(e) None of these
Q14. For which course is the number of boys the minimum?
(a) E
(b) F
(c) C
(d) A
(e) None of these
S14. Ans.(d)
Sol. Number of boys for different courses are
A = 0; B = 100; C = 44; D = 180; E = 32; F = 44.
Q15. How many girls are there in course C?
(a) 44
(b) 16
(c) 40
(d) 160
(e) None of these
S15. Ans.(b)
Sol. Number of girls in course C = 2% of 800 = 16.
