Quantitative Aptitude

Quant Quiz (Problems On Ages) With Solutions

1. Ashok's age is (1/6) th of his father's age. The father's age will be twice of Kamal's age after 10 years. 
If Kamal's eighth birthday was celebrated 2 years before, what is Ashok's present age?

(a) 24 years

(b) 30 years

(c) 6(2/3) years

(d) None of these

(e) Cannot be determined

Sol. 

1. (d); Kamal's present age=10 years

Kamal's age after 10 years=20 years

Father's age after 10 years =40 years

Father's age now=30 years

Ashok's age now=[(1/6)X30]years=5 years

2. The sum of the ages of a father and son is 45 years. Five years ago the product of their ages was 4 times the father's age at that time. 
The present ages of the father and son respectively are:

(a) 25 years, 10 years

(b) 36 years, 9 years

(c) 39 years, 6 years

(d) None of these

(e) Cannot be determined

Sol.

2. (b); Let son's age=x. Then, father's age=(45-x)

(x-5) (45-x-5)=4(45-x-5)

x-5=4

x=9

Therefore, Father's age now=36 years & son's age=9 years.

3. 10 years ago, Mona's mother was 4 times older than her daughter. After 10 years, the mother will be twice older than the daughter. Mona's present age is:

(a) 5 years

(b) 10 years

(c) 20 years

(d) 30 years

(e) None of these

Sol.

3. (c); Let Mona's age 10 yrs ago=x. Her mother's age then=4x.

2(x+20)=4x+20

2x=20

x=10

Therefore, Mona's present age=(10+10)years=20 years

4. Three years ago, the average age of A and B was 18 years. With C joining them, the average becomes 22 years. How old is C now?

(a) 24 years

(b) 27 years

(c) 28 years

(d) 30 years

(e) None of these

Sol.

4. (a); (A+B)'s age 3 years ago=(18X2)=36 years

(A+B) now=(36+3X2)years=42 years.

(A+B+C) now=(3X22) years=66 years.

C's present age=(66-42) years=24 years.

5. Kamla got married 6 years ago. Today her age is 1(1/4) times her age at the time of marriage. He son's age is 1/10 times her age. Her son's age is:

(a) 2 years

(b) 3 years

(c) 4 years

(d) 5 years

(e) None of these

Sol.

5. (b); Let Kamla's age 6 years ago be x.

therefore, (x+6)=(5/4)x

4(x+6)=5x

x=24

therefore, Kamla's present age=30 years.

therefore, Kamla's son's present age=[(1/10)X30] years=3 years

6. One year ago the ratio of Varun and Veena's ages was 4 : 5. One year hence the ratio of their ages will be 5 : 6. The present age of Veena is:

(a) 9 years

(b) 10 years

(c) 12 years

(d) 6 years

(e) None of these

Sol.

6. (c); Let their ages 1 years ago be 4x and 5x.

[(4x+2)/(5x+2)]=5/6

6(4x+2)=5(5x+2)

x=2 

therefore, Veena's present age=(5x+2)=12 years.

7. A is as much younger to B as he is older to C. If the sum of the ages of B and C is 48 years, what is the present age of A?

(a) 20 years

(b) 24 years

(c) 30 years

(d) 36 years

(e) None of these

Sol. 

7. (b); B-A=A-C

2A=B+C

2A=48

A=24

8. Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what is the sum of their present ages?

(a) 8 years

(b) 20 years

(c) 35 years

(d) 45 years

(e) None of these

Sol.

8. (c); Let their present ages be 3x and 4x. Then,

2(3x-10)=4x-10

2x=10

x=5

therefore, Sum of their present ages=7x=35 years.

9. The ratio of Laxmi's age to the age of her mother is 3 : 11. The difference of their ages is 24 years. The ratio of their ages after 3 years will be:

(a) 1 : 3

(b) 2 : 3

(c) 3 : 5

(d) 2 : 5

(e) None of these

Sol.

9. (a); Let their ages be 3x & 11x.

11x-3x=24

x=3

Their present ages are 9 years & 33 years. 

Ratio of their ages after 3 years = 12 : 36 =1 : 3

10. The age of a man is 4 times that of his son. Five years ago, the man was nine times as old as his sone was at that time. The present age of the man is:

(a) 28 years

(b) 32 years

(c) 40 years

(d) 44 years

(e) None of these

Sol.

10. (b); Let the son's age be x. Then, father's age=4x.

therefore, (4x-5)=9(x-5)

5x=40

x=8

therefore, Present age of the man=32 years.