PERCENTAGE

PERCENTAGE

Dear readers, here we are providing some questions on Percentage  which will helpful in your upcoming SSC exam

1.    A number increased by 20% and then decreased by 20%. Finally the number is:

(a) Decreased by 4%              (b) increased by 4%

(c) Does not change                (d) decreased by 0.4%

2.    Two numbers are less than third number by 30% and 37% respectively. How much percent is the second number less than by the first

(a) 20%                                    (b) 30 %

(c) 10%                                    (d) 40%

3.    In an examination, 34% of the students failed in mathematics and 42% failed in English.

       If 20% of the students failed in both the subjects, then find the percentage of students who passed in both the subjects.

(a) 40%                                     (b) 41%

(c) 43%                                     (d) 44%

4.    In the new budget, the price of kerosene oil rose by 25%. By how much percent must a person reduce -

      his consumption so that his expenditure on it does not increase?

(a) 20%                                   (b) 30%

(c) 22%                                   (d) 24%

5.    The value of a machine depreciates at the rate of 10% per annum. If its present is Rs.1, 62,000. What was the value of the machine 2 years ago?

(a) 200000                               (b) 20000

(c) 2000                                    (d) None of these

6.    A student multiplied a number by 3/5 instead of 5/3. What is the percentage error in the calculation?

(a) 60%                                     (b) 62%

(c) 64%                                     (d) 65%

7.    Two number x and y are respectively 20% and 50% more than a third number x is how month percent of y?

(a) 30 %                                    (b) 45%                     

(c) 60 %                                   (d) 80%

8.    13% of a number exceeds 5% of the same by 16. The number is :

(a) 500                                      (b) 450

(c) 300                                      (d) 200

9.    If A exceeds B by 60% and B is less than C by 20%, then A:C is

(a) 32:25                                  (b) 25:32

(c) 8:5                                       (c) 4:5

10.  In an examination, a student had to obtain 33% of the maximum marks to pass. He got 125 marks 

        and failed by 40 marks .the maximum marks were :

(a) 500                                    (b) 600

(c) 800                                     (d) 1000

 ANSWERS WITH EXPLANATIONS:

1.    (a):

Final change = a²/100 à (20*20)/100,  4% decrease

2.    (c):

Let the third number is x.
then first number = (100-30)% of x = 70% of x = 7x/10

Second number is (63x/100)
Difference = 7x/10 - 63x/100 = 7x/10
So required percentage is, difference is what percent of first number
=> (7x/100 * 10/7x * 100 )% = 10%

3.    (d):

Failed in mathematics, n(A) = 34
Failed in English, n(B) = 42

n(AUB) = n(A) + n (B) – n (A∩ B )

= 34 + 42- 20 = 56
Failed in either or both subjects are 56

Percentage passed = (100−56)%=44%

4.    (a):

Reduction in consumption = [((R/(100+R))*100]%
 [(25/125)*100]%=20%.

5.    (a):

 Value of the machine 2 years ago
= Rs.[162000/(1-(10/100)²)]=Rs.[162000*(10/9)*(10/9)]= Rs.200000

6.    (c):

Let the number be x

Then, error =  (5/3)x – (3/5)x =(16/15)x

Error% = [(16x/15) /(5x/3)] * 100% = 64%

7.    (d):

Let the third number is 100

∴The number x = 120 and the number y = 150

∴ x is how much percent of y = x*100/y = 120*1oo/150  = 80%

8.    (d):

Let the number is X

∴13% of the x-5% of x = 16

∴13*x/100 – 5*x/100 = 16 àX = 200

9.    (a):

Let the C = 100 then the B = 80

And A = 80*160/100 = 128

∴ A : C 128:100 = 32:25

10.  (a):

Let the maximum marks were x

∴x*33/100 = 125+40 =165

∴x = 165*100/33 = 500